STEP1 构造测试表和数据
复制代码
CREATE TABLE TEST111 (ID INT );
INSERT INTO TEST111 VALUES (1);
INSERT INTO TEST111 VALUES (2);
INSERT INTO TEST111 VALUES (3);
COMMIT;
DROP TABLE TEST222;
CREATE TABLE TEST222 (ID INT );
INSERT INTO TEST222 VALUES (1);
INSERT INTO TEST222 VALUES (2);
INSERT INTO TEST222 VALUES (NULL);
COMMIT;
复制代码
STEP2
--标量子查询
SELECT T1.ID,(SELECT T2.ID AS T2ID FROM TEST222 T2 WHERE T2.ID = T1.ID) FROM TEST111 T1;

--左连接 等同于标量子查询
SELECT T1.ID,T2.ID FROM TEST111 T1,TEST222 T2 WHERE T1.ID = T2.ID(+);
--等值查询
SELECT T1.ID,T2.ID FROM TEST111 T1,TEST222 T2 WHERE T1.ID = T2.ID;

有经验的开发不员不难看出二者的区别。
下面大家思考一下下面的语句是等价的吗,若果不是,要怎么改写呢
select a.username, count(*)
from all_users a, all_objects b
where a.username = b.owner (+)
group by a.username order by a.username;
select a.username, (select count(*) from all_objects b where b.owner = a.username) cnt from all_users a
group by a.username order by a.username;
大家不妨试着执行看下结果,可以看到是有差异的。那么该如何改呢,
select a.username, count(owner)
from all_users a, all_objects b
where a.username = b.owner (+)
group by a.username order by a.username;
因为count(*) 在b表无记录匹配的情况下,也会返回1。
另外还需要说明的是:
count(*)与count(1)包含null列统计,count(id),统计id不为null的列和。
总结:项目中如果遇到需要写标量子查询的地方,不妨先按上面的内容思考下,是否会出现包含不想要的结果。
复制代码
CREATE TABLE TEST111 (ID INT );
INSERT INTO TEST111 VALUES (1);
INSERT INTO TEST111 VALUES (2);
INSERT INTO TEST111 VALUES (3);
COMMIT;
DROP TABLE TEST222;
CREATE TABLE TEST222 (ID INT );
INSERT INTO TEST222 VALUES (1);
INSERT INTO TEST222 VALUES (2);
INSERT INTO TEST222 VALUES (NULL);
COMMIT;
复制代码
STEP2
--标量子查询
SELECT T1.ID,(SELECT T2.ID AS T2ID FROM TEST222 T2 WHERE T2.ID = T1.ID) FROM TEST111 T1;

--左连接 等同于标量子查询
SELECT T1.ID,T2.ID FROM TEST111 T1,TEST222 T2 WHERE T1.ID = T2.ID(+);
--等值查询
SELECT T1.ID,T2.ID FROM TEST111 T1,TEST222 T2 WHERE T1.ID = T2.ID;

有经验的开发不员不难看出二者的区别。
下面大家思考一下下面的语句是等价的吗,若果不是,要怎么改写呢
select a.username, count(*)
from all_users a, all_objects b
where a.username = b.owner (+)
group by a.username order by a.username;
select a.username, (select count(*) from all_objects b where b.owner = a.username) cnt from all_users a
group by a.username order by a.username;
大家不妨试着执行看下结果,可以看到是有差异的。那么该如何改呢,
select a.username, count(owner)
from all_users a, all_objects b
where a.username = b.owner (+)
group by a.username order by a.username;
因为count(*) 在b表无记录匹配的情况下,也会返回1。
另外还需要说明的是:
count(*)与count(1)包含null列统计,count(id),统计id不为null的列和。
总结:项目中如果遇到需要写标量子查询的地方,不妨先按上面的内容思考下,是否会出现包含不想要的结果。
0人赞
分享
二维码
赏一个